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28n^2-176n+48=0
a = 28; b = -176; c = +48;
Δ = b2-4ac
Δ = -1762-4·28·48
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25600}=160$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-176)-160}{2*28}=\frac{16}{56} =2/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-176)+160}{2*28}=\frac{336}{56} =6 $
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